Dry air was passed successively
WebNov 9, 2024 · Dry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure ware. The loss in weight of solution was 2.50 gm and that of pure solvent 0.04 gm. A. `70.31` B. `7.143` C. `714.3` D. 80 class-12 solution Share It On FacebookTwitterEmail Please log inor registerto add a comment. http://www.word-detective.com/2009/07/dry-run/
Dry air was passed successively
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WebQ. Dry air was passed successively through a solution of 5 g of a solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure … WebDry air was passed successively through a solution of 5 g of a solute in 1 8 0 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0. 0 4 g. The molecular weight of the solute is: Medium. View solution > View more. More From Chapter.
WebDry air was passed successively through a solution of 5gm of a solute in 80gm of water and then through pure water. The loss in weight of the solution was 2.50gm and that of … WebDry air was passed successively through a solution of 5 g of a solute in 1 8 0 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0. 0 4 g. The molecular weight of the solute is:
Web. Dry air was passed successively through a solution of 5 g solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent is 0.04 g. The molecular weight of the solute is A. 31.75 B. 3.125 C. 312.5 D. None of the above Best Answer Ans: A Sol: WebDry air was passed successively through a solution of 5 g of a solute in 1 8 0 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0. 0 4 g. The molecular weight of the solute is:
WebJan 31, 2024 · A current of dry air was passed through a solution of 2.64g of benzoic acid in 30g of ether (C2H5OC2H5) and then through pure ether. The loss in weight of the solution was 0.64g and that of ether was 0.0345g. Calculate the molecular mass of benzoic acid (122g/mol). Solution Weight of solution W1 = 0. 645g Weight of solvent W2 = 0.0345g
WebMethod: In this method, a stream of dry air is passed successively through (i) a solution (ii) the pure solvent (water) and (iii) a reagent (anhydrous CaCl 2) that can absorb the vapours of the solvent. The complete assembly is shown in the figure, given below: Ostwald - Walker Experiment bearing 628/8WebDry air was passed successively through a solution of 5 g of a solute in 180 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0.04 g. The molecular weight of the solute is: Medium View solution > View more More From Chapter Solutions View chapter > Revise with Concepts bearing 628-2zWebJul 24, 2024 · Dry air was passed successively through a solution of \\( 5 \\mathrm{~g} \\) of a solute in \\( 80 \\mathrm{~g} \\) of water and then through pure water. The loss ... bearing 625zzWebDry air was passed successively through a solution of \( 5 \mathrm{gm} \) of a solute in \( 180 \mathrm{gm} \) of water and then through pure water. The loss... dibujos a lapiz de anime kawaibearing 628/5-2zWebDry air was passed successively through a solution of 5 g of a solute in 1 8 0 g of water and then through pure water. The loss in weight of solution was 2.50 g and that of pure solvent 0. 0 4 g. The molecular weight of the solute is: bearing 628zWebDry air was passed successively through a solution of 5 g a solute in 80 g of water and then through pure water. The loss in mass of solution was 2.5 g and that pure solvent was 0.04 g. dibujo rama ejecutiva